Charleston Open: Alexandrova sets up Bencic rematch in quarters
The Russian is tied with Bencic at 3-3 in their head-to-head
Russian Ekaterina Alexandrova, the No 7 seed, advanced to the last eight of the Charleston Open by defeating Austrian Julia Grabher 6-4, 6-2 at the Family Circle Tennis Center on Thursday.
Alexandrova, ranked No 17, will face Swiss Belinda Bencic, the No 4 seed, in a rematch of the semi-final last year which the Swiss woman won en route to winning the title.
The pair are tied at 3-3 in their head-to-head and Alexandrova won their most recent encounter, last month in Miami in straight sets.
The Russian won against Kazakh Yulia Putintseva (6-1, 6-3) in the previous round of the Charleston tournament.
Grabher, ranked No 89, won against Chinese Shuai Zhang, the No 10 seed (6-4, 1-6, 6-3) and American qualifier Sachia Vickery (6-1, 6-2) earlier in the week.
Charleston WTA 500, other round of 16 results (Family Circle Tennis Center, clay, USD 780,637)
- Ons Jabeur (2) beat Caroline Dolehide (WC): 6-3, 7-5
- Anna Kalinskaya beat Victoria Azarenka (6): 6-4, 7-6 (5)
- Paula Badosa (12) beat Diana Shnaider: 6-1, 6-3
- Magda Linette vs. Madison Keys
- Belinda Bencic vs. Shelby Rogers
- Bernarda Pera vs. Daria Kasatkina
- Jessica Pegula vs. Irina-Camelia Begu