Dubai Open: Defending champion Rublev advances to last four; plays Zverev next
Andrey Rublev beat Botic van de Zandschulp 6-3, 7-6 (3) on Thursday afternoon. He’ll play German Alexander Zverev, the No 7 seed, in the next round
Imago / Panoramic
Russian Andrey Rublev, the second seed, advanced to the semi-finals of the Dubai Open by winning against Dutchman Botic van de Zandschulp 6-3, 7-6 (3) at the Aviation Club Tennis Centre on Thursday.
Rublev, ranked No 6, will play German Alexander Zverev, the No 7 seed, next.
Ahead of his victory, the Russian defeated Serb Filip Krajinovic (7-5, 6-2) and edged out Spaniard Alejandro Davidovich Fokina (1-6, 7-6 (6), 7-6 (3)), saving five match points before scrambling through.
Van De Zandschulp, ranked No 33, beat Russian Karen Khachanov, the No 6 seed (7-5, 6-2) and Swede Mikael Ymer (3-6, 6-3, 6-3) earlier in the tournament.
Dubai ATP500, other last eight results (Aviation Club Tennis Centre, hard, USD 2.855.495, most recent results first):
- Daniil Medvedev vs. Borna Coric
- Novak Djokovic vs. Hubert Hurkacz
- Alexander Zverev beat Lorenzo Sonego: 7-5, 6-4
People in this post
More tennis news
Denmark, Lyon, Roland-Garros: All you need to know about Clara Tauson but never had the time to find out – updated after reaching Dubai final 2025
February 23, 2006: The day Yaroslava Shvedova came within one point of achieving the first golden set in women’s tennis history
Alexandre Muller reaches maiden 500 final in Rio
Mirra’s mission: Andreeva targets top-5 by the end of 2025
Defending champion Baez moves into final in Rio
